## Patterns

Hi! Today in math, we used a site called Math Playground. We made patterns using shapes such as triangles and square. The first pattern that I made is right here: This is a ABA pattern. I used trapezoids and triangles to make it.

The second one that I made is this one: This is a ABAA pattern. This one includes triangles and squares. So that’s it for this post, hope you enjoyed and BYE!!! 🙂

## Patterns

Hi! This blog post is about our math class today which was about patterns.

First, we saw different types of patterns on the board; we had to find out what kind of pattern is it and the core of it. Then we had some practices of us making some patterns, after that we had to make our own. My partner was Sophie, we made two patterns that are in the pictures down below. 👇🏻 One of them is a growing pattern, and the other one is a AB pattern.  That’s it for today’s post, BYE!

## Proportions

Today, in math we learnt about proportions. A proportion is a pair of equivalent ratios. It has to have a same value and unit to be a proportion. We watched a video which helped us understand proportions better. Here are some examples:  ## Math Test Reflection : Unit 4 Decimals On the first of October, we had a math test about decimals. This time I think I did pretty well, since I got quite a lot of the questions correct. At first I was really worried that I wouldn’t do good, but at the end, I think I did really well. As Mr. Roberts also said, I am ready for challenges. For me, I would say the comparison of decimals are the easiest; and the word problems are the hardest just because sometimes they were really confusing, but I glad to get them correct at the end.

## Home Learning-Math

Hi! For my math home learning, it is about using different ways to solve 23x4 without using 4.

23+23+23+23=92

1. 23x(1+3)=92
1. 23×2+23×2=92
1. (3.5+0.5)x23=92

5. (8 divide 2)x23=92

6.(2+2)x23=92

7.(10-6)x23=92

Those are some ways to solve 23×4 without using 4.

## Home Learning-Stand Alone Math

Leftovers

You have some counters.

You put them into groups of three, and there is one counter left over. If you put the same  counters into groups of four, there are three counters left over.

A) How many counters could you have?       19, 31, 43, 55

B) How many different ways can you find to do this?     One way I solve it is by adding 12

C) How many counters might you have had if the total number of counters was more than 50?           55, 67, 79, 91, 103. It could go on forever.